Computer Shopper 125/Computer Shopper CD-ROM Issue 125 (1998-07)(Dennis Publishing).iso/EuroMath/MathDemo/DataBase/Question/ID453.txt

Text File | 1997-09-04 | 8.6 KB | 474 lines

M"'(O)o(O)o(O)o(O)o(O)o(O)o(O)o(O)o(O)o(O)o(O)
'o(O)
'(O)o
'o(O)        n0107 - Question B
'(O)o
'o(O)        Lowest Common Multiple
'(O)o
'o(O)
'(O)o(O)o(O)o(O)o(O)o(O)o(O)o(O)o(O)o(O)o(O)


@WeightingScore 9,1,1,1

@atGraphic 36,14
@Picture numbers\n0107a.bmp

@at 100,20
Find the #blowest common #
#bmultiple# of the following
numbers:
@at 10,+8
                   #^   #p6#         #^   #p5#         #^  #p10#

@at 10,+62
  Which method do you want to practice?
@at ,+6
   Listing the #bmultiples# of each number...
@at ,+4
   Using #bprime numbers#...

@MultMode 2
@atGraphic 214,156
@Loop 2
@HSPicture uncheck.bmp,check.bmp
@atGraphic ,172
@EndLoop

@Answer 0,2
@Feedback 0
@FBMGoto Method_2
@Answer 0,1

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@Question

@at 10,+32
What's the first step?
@at ,+3
#[K]

@keyPointAnswer 1,185,multiply by 2

@KeyPointFeedback 0,Wrong option
The first step will be to find all the
factors of each number.


'|||||||||||||||||||/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/|||||||||||||||||||||

@Question

@NewPage
@atGraphic 36,14
@Picture numbers\n0107a.bmp

@at 100,20
Find the #blowest common #
#bmultiple# of the following
numbers:
@at 10,+8
       #^            #^   #p6#         #^   #p5#         #^  #p10#

@InputWidth 20
@at ,+2
#T╫2 #T#[N]#T#[N]#T#[N]
@MarkPos 1

@Answer 1, 12,10,20

@Feedback E0.33,?,?,?
That's partly right.*
@Feedback 0,?,?,?

@FeedbackC 1,  6 ╫ 2 = #b12#
@FeedbackC 2,  5 ╫ 2 = #b10#
@FeedbackC 3,10 ╫ 2 = #b20#
@FeedbackC 0,
@FeedbackC 0,Always check your answers.


'/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/

@Question

@at 10,+140
What's the next step?
@at ,+3
#[K]
@MarkPos 2

@keyPointAnswer 1,186,multiply by one more than last time

@KeyPointFeedback 0,Wrong option
Continue finding the multiples of each number
until you find the lowest common multiple,
which will appear in all three lists.


'/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/


@Question

@GoPos 1
@at ,+5
#T╫3 #T#[N]#T#[N]#T#[N]
@at ,+5
#T╫4 #T#[N]#T#[N]#T#[N]
@at ,+5
#T╫5 #T#[N]#T#[N]#T#[N]
@at ,+5
#T╫6 #T#[N]#T#[N]#T#[N]

@Answer 5, 18,15,30, 24,20,40, 30,25,50, 36,30,60

@Feedback E0.4, ?,?,?,?,?,?,?,?,?,?,?,?
@Feedback 0, ?,?,?,?,?,?,?,?,?,?,?,?

@FeedbackC 0,To find the lowest common multiple of a of
@FeedbackC 0,number, multiply them by whole numbers beginning
@FeedbackC 0,with 2, and continuing with ╫3, ╫4, ╫5, etc. until
@FeedbackC 0,there is a multiple common to all the numbers.*
@FeedbackC 0,Remember to check your answers.


'/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/

@Question

@InputWidth 26
@GoPos 1
@at 80,+80

#b       Lowest#
#bCommon Multiple#
@at ,+3
            #[N]

@Answer 1, 30

@Feedback 0,?
You should have found the lowest number in all
the lists.  #b30# is the lowest multiple common
to all three numbers.

@Feedback 1
That's right!  Well done.

@Goto End_of_Question



'<\/>/\<\/>/\<\/>/\<\/>/\<\/>/\<\/>/\<\/>/\<\/>/\<\/>     METHOD 2    <\/>/\<\/>/\<\/>/\<\/>/\<\/>/\<\/>/\<\/>/\<\/>/\<\/>



@Label Method_2

@Question

@at 10,+32
What's the first step?
@at ,+3
#[K]

@keyPointAnswer 1,187,find the prime factors of each number

@KeyPointFeedback 0,Wrong option
The first step will be to find all the
prime factors of each number.


'|||||||||||||||||||/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/|||||||||||||||||||||

@NewPage
@atGraphic 36,14
@Picture numbers\n0107a.bmp

@at 100,20
Find the #blowest common #
#bmultiple# of the following
numbers:
@at 10,+8
   #^            #p6#         #^           #p5#         #^          #p10#;
#T ;
@MarkPos 1
#T#T ;
@MarkPos 2
#T#T#T ;
@MarkPos 3

@InputWidth 20
@GoPos 1
#^        #^;
@Loop 2
#T#[N];
@at ,+17
#T#T#[N];
@EndLoop

@Answer 1.5, 2,3,3,1

@Feedback E0.375,?,?,?,?
@Feedback 0,?,?,?,?

@FeedbackC 0,To find all the prime factors of any number,
@FeedbackC 0,first divide by the smallest prime number as
@FeedbackC 0,many times as possible.  If the number will
@FeedbackC 0,not divide evenly, divide by the next larger
@FeedbackC 0,prime number, and repeat until you are left
@FeedbackC 0,with a result of 1.


'/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/


@Label Next
@Question

@GoPos 1
@at 20,+90
The Prime Factors are...

@InputWidth 14
@GoPos 1
@at -6,+120
#[N];
@at ,-10
#[N];
@at ,+10
 ╫ #[N];
@at ,-10
#[N]

@Answer 0.5, 2,,3,1
@Feedback 0.5
@FBMGoto Next
@Answer 0.5, 2,1,3,
@Feedback 0.5
@FBMGoto Next
@Answer 0.5, 3,,2,1
@Feedback 0.5
@FBMGoto Next
@Answer 0.5, 3,1,2,
@Feedback 0.5
@FBMGoto Next

@Answer 0.5, 2,,3,
@Feedback 0.5
@FBMGoto Next
@answer 0.5,3,,2,
@Feedback 0.5
@FBMGoto Next
@Answer 0.5, 3,1,2,1
@Feedback 0.5
@FBMGoto Next
@Answer 0.5, 2,1,3,1

@Feedback E0.125,?,?,?,?
@Feedback 0,?,?,?,?

@FeedbackC 0,Once you've worked out all the prime factors,
@FeedbackC 0,you should rewrite each factor once, raising
@FeedbackC 0,it to an index to show how many lots there
@FeedbackC 0,are.


'/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/

@Label Next
@Question

@InputWidth 20
@GoPos 2
#^        #^;
@Loop 2
#T#[N];
@at ,+17
#T#T#[N];
@EndLoop

@Answer 1.5, 5,1,,

@Feedback E0.375,?,?,?,?,?,?
@Feedback 0,?,?,?,?,?,?

@FeedbackC 0,To find all the prime factors of any number,
@FeedbackC 0,first divide by the smallest prime number as
@FeedbackC 0,many times as possible.  If the number will
@FeedbackC 0,not divide evenly, divide by the next larger
@FeedbackC 0,prime number, and repeat until you are left
@FeedbackC 0,with a result of 1.


'/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/


@Label Next
@Question

@InputWidth 14
@GoPos 2
@at +20,+120
#[N];
@at ,-10
#[N]

@Answer 0.5, 5,
@Feedback 0.5
@FBMGoto Next
@Answer 0.5, 5,1

@Feedback E0.25,?,?
@Feedback 0,?,?

@FeedbackC 0,Once you've worked out all the prime factors,
@FeedbackC 0,you should rewrite each factor once, raising
@FeedbackC 0,it to an index to show how many lots there
@FeedbackC 0,are.

'/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/


@Label Next
@Question

@InputWidth 20
@GoPos 3
#^        #^;
@Loop 2
#T#[N];
@at ,+17
#T#T#[N];
@EndLoop

@Answer 1.5, 2,5,5,1

@Feedback E0.375,?,?,?,?
@Feedback 0,?,?,?,?

@FeedbackC 0,To find all the prime factors of any number,
@FeedbackC 0,first divide by the smallest prime number as
@FeedbackC 0,many times as possible.  If the number will
@FeedbackC 0,not divide evenly, divide by the next larger
@FeedbackC 0,prime number, and repeat until you are left
@FeedbackC 0,with a result of 1.


'/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/


@Label Next
@Question

@InputWidth 14
@GoPos 3
@at +4,+120
#[N];
@at ,-10
#[N];
@at ,+10
 ╫ #[N];
@at ,-10
#[N]


@Answer 0.5, 2,,5,1
@Feedback 0.5
@FBMGoto Next
@Answer 0.5, 2,1,5,
@Feedback 0.5
@FBMGoto Next
@Answer 0.5, 5,,2,1
@Feedback 0.5
@FBMGoto Next
@Answer 0.5, 5,1,2,
@Feedback 0.5
@FBMGoto Next
@Answer 0.5, 2,,5,
@Feedback 0.5
@FBMGoto Next
@answer 0.5,5,,2,
@Feedback 0.5
@FBMGoto Next
@Answer 0.5, 5,1,2,1
@Feedback 0.5
@FBMGoto Next
@Answer 0.5, 2,1,5,1

@Feedback E0.125,?,?,?,?
@Feedback 0,?,?,?,?

@FeedbackC 0,Once you've worked out all the prime factors,
@FeedbackC 0,you should rewrite each factor once, raising
@FeedbackC 0,it to an index to show how many lots there
@FeedbackC 0,are.


'/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/

@Label Next
@Question

@at 10,280
Now what do you do?
@at ,+3
#[K]

@keyPointAnswer 1,188,find the product

@KeyPointFeedback 0,Wrong option
The final step is to find the product of
each unique prime factor.


'/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/

@Question

@InputWidth 20
@at 10,220
        Lowest Common Multiple  =
@at 10,+14
  #[N];
@at ,-10
#[N];
@at ,+10
  ╫  #[N];
@at ,-10
#[N];
@at ,+10
  ╫  #[N];
@at ,-10
#[N];
@at ,+10
  =  #[N]

@Answer 1, 1&3&5=2|3|5, , *, , *, , 30
@Feedback 1
@FBMgoto Right
@Answer 1, 1&3&5=2|3|5, 1, *, 1, *, 1, 30

@Feedback 0.5, 2, 1,3, 1,5, 1, ?
@Feedback 0.5, 2, ,3, ,5, , ?
@FBMGoto Calc

@Feedback 0,?,?,?,?,?,?,?
To find the lowest common multiple,
@Label Calc
The lowest common multiple of 6, 5 and 10 is:*
                  #b2ç ╫ 3ç ╫ 5ç# = #b30#

@Label Right
@Feedback 1
That's right!  Well done.


'<\/>/\<\/>/\<\/>/\<\/>/\<\/>/\<\/>/\<\/>/\<\/>/\<\/>


@Label End_of_Question